Mathematics - Circle Question with Solution | TestHub
MathematicsCircleFamily of circlesMedium2 minQB
MathematicsMediumsingle choice
Passage / Comprehension
For Q87-89: A=(0,0), B=(4,0), and P varies with PA=K·PB, where K>0 and K≠1. Its locus is a circle S, meeting AB at D and E.
and varies with . Its locus is a circle , meeting at . If a circle through bisects the circumference of , the radius of is
Options:
Answer:
UNKEYABLE AS PRINTED
Solution:
Even if Q37 fixes and has centre ( ) and radius , a circle through whose intersection chord with passes through the centre of has a free centre parameter. Its radius is not uniquely fixed. The source key A lacks an additional condition.
Stream:JEESubject:MathematicsTopic:CircleSubtopic:Family of circles
⏱ 2mℹ️ Source: QB
Doubts & Discussion
Loading discussions...
