Choose the correct statement about two circles whose equations are given below:
$x^{2} + y^{2} - 10 x - 10 y + 41 = 0$
$x^{2} + y^{2} - 22 x - 10 y + 137 = 0$

Question

Choose the correct statement about two circles whose equations are given below: x 2 + y 2 - 10 x - 10 y + 41 = 0 x 2 + y 2 - 22 x - 10 y + 137 = 0

TestHub · Accepted Answer

x 2 + y 2 - 10 x - 10 y + 41 = 0 A ( 5 , 5 ) , R 1 = 3 x 2 + y 2 - 22 x - 10 y + 137 = 0 B ( 11 , 5 ) , R 2 = 3 A B = 6 = R 1 + R 2 Touch each other externally ⇒ circles have only one meeting point.

Mathematics - Circle Question with Solution | TestHub

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