Mathematics - Circle Question with Solution | TestHub

The centre of the given circle is $\mathrm{C}\equiv (4,2)$ Let $A\equiv (-3,2)$
If $(\alpha ,\beta )$ are the coordinates of the other end of the diameter, then, as the middle ploint of the diameter is the centre, $\therefore \frac{\alpha -3}{2}=4$ and $\frac{\beta +2}{2}=2\Rightarrow \alpha =11,\beta =2$ Thus, the coordinates of the other end of diameter are (11,2)