Mathematics - Circle Question with Solution | TestHub

The equation of circle is, $x^2+y^2-6x+8y-103=0$ $\Rightarrow (x-3{)}^2+(y+4{)}^2=(8\sqrt{2}{)}^2$ $C(3,-4),r=8\sqrt{2}$ $\Rightarrow$ Length of side of square $=\sqrt{2}r=16$
$\Rightarrow P(-5,4),Q(-5,-12)$ $R(11,-12),S(11,4)$ $\Rightarrow$ Required distance $=OP$ $=\sqrt{(-5-0{)}^2+(-4-0{)}^2}=\sqrt{25+16}=\sqrt{41}$