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MathematicsCircleMiscellaneous/MixedMedium2 minPYQ_2016
MathematicsMediummultiple choice

Let RS be the diameter of the circlex2+y2=1where,Sis the point(1, 0). LetP be a variable point (other thanR & S) on the circle and tangents to the circle atS & P meet at the pointQ. The normal to the circle at P intersects a line drawn throughQparallel toRSat pointE. Then, the locus ofEpasses through the point (s):

Question diagram: Let RS be the diameter of the circle x 2 + y 2 = 1 where, S

Options:(select one or more)

Answer:
A, C
Solution:


Let P be  (cos θ , sin θ), where
θ 0,π
Tangent atP :xcosθ+ysinθ=1........(i)
Tangent atS :x=1.........(ii)
By (i) and (ii) :Q1,1-cosθsinθ
Line through Q parallel to RS :
y=1-cosθsinθ     y=tanθ2..........(iii)
Normal atP :y=sinθcosθx    y=tanθ.xy=2tanθ21-tan2θ2x........(iv)
Point of intersection of equation (iii) and (iv),E :h=1-tan2θ22;k=tanθ2
Eliminatingθ :h=1-k22      y2=1-2x
( 1 3 , 1 3 ) & ( 1 3 , 1 3 ) satisfy the locus.

Stream:JEE_ADVSubject:MathematicsTopic:CircleSubtopic:Miscellaneous/Mixed
2mℹ️ Source: PYQ_2016

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