Mathematics - Circle Question with Solution | TestHub

MathematicsCircleMiscellaneous/MixedMedium2 minPYQ_2013

MathematicsMediumsingle choice

If the circle $x^{2} + y^{2} - 6 x - 8 y + (25 - a^{2}) = 0$ touches the axis of $x$ , then a equals.

Answer:

Solution:

$x^{2} + y^{2} - 6 x - 8 y + (25 - a^{2}) = 0 Radius = 4 = 9 + 16 + (25 - a^{2}) \Rightarrow a = \pm 4$

Stream:JEESubject:MathematicsTopic:CircleSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2013

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