Mathematics - Circle Question with Solution | TestHub

MathematicsCircleMiscellaneous/MixedMedium2 minPYQ_2008

MathematicsMediumsingle choice

The point diametrically opposite to the point $P (1, 0)$ on the circle $x^{2} + y^{2} + 2 x + 4 y - 3 = 0$ is

Answer:

Solution:

Centre $(- 1, - 2)$ Let $(α, β)$ is the required point $\frac{α + 1}{2} = - 1$ and $\frac{β + 0}{2} = - 2$ .

Stream:JEESubject:MathematicsTopic:CircleSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2008

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