If the lines 3 x − 4 y − 7 = 0 and 2 x − 3 y − 5 = 0 are two diameters of a circle of area 49 π square units, the equation of the circle is

Question

TestHub · Accepted Answer

Point of intersection of 3 x − 4 y − 7 = 0 and 2 x − 3 y − 5 = 0 is ( 1 , − 1 ) , which is the centre of the circle and radius = 7 . ∴ Equation is ( x − 1 ) 2 + ( y + 1 ) 2 = 49 ⇒ x 2 + y 2 − 2 x + 2 y − 47 = 0

Mathematics - Circle Question with Solution | TestHub

Options:

Doubts & Discussion