Mathematics - Binomial Theorem Question with Solution | TestHub

${\left(1-3x+3x^2-x^3\right)}^{2n}=(1-x{)}^{6n}$ Concept: Index $=6n$ which is even so most middle term is ${\left(\frac{6n}{2}+1\right)}^{\text{th }}$ i.e., $(3n+1{)}^{\text{th }}$ term is middle term, $T_{3n+1}={}^{6n}{C}_{3n}(-x{)}^{3n}=\frac{6n!}{3n!3n!}(-x{)}^{3n}$