Let ( 1 + x + x 2 ) 20 ( 2 x + 1 ) = a 0 + a 1 x 1 + a 2 x 2 + … + a 41 x 41 , then 1 a 0 + 2 a 1 + … . + 42 a 41 is λ , which of the following is/are CORRECT?

∫ ( 1 + x + x 2 ) 20 ( 2 x + 1 ) d x = 1 a 0 + 2 a 1 + … . + 42 a 41

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Mathematics - Binomial Theorem Question with Solution | TestHub

MathematicsBinomial TheoremGeneralMedium2 minQB

MathematicsMediummultiple choice

Let $(1 + x + x^{2})^{20} (2 x + 1) = a_{0} + a_{1} x^{1} + a_{2} x^{2} + \dots + a_{41} x^{41}$ , then $\frac{a _{0}}{1} + \frac{a _{1}}{2} + \dots . + \frac{a _{41}}{42}$ is $λ$ , which of the following is/are CORRECT?

Options:(select one or more)

Answer:

B, C

Solution:

$\int (1 + x + x^{2})^{20} (2 x + 1) d x = \frac{a _{0}}{1} + \frac{a _{1}}{2} + \dots . + \frac{a _{41}}{42}$

Stream:JEESubject:MathematicsTopic:Binomial TheoremSubtopic:General

⏱ 2mℹ️ Source: QB

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