Mathematics - Binomial Theorem Question with Solution | TestHub

For $\mathrm{x}=1$ ${\left(1+\frac{2}{5}\right)}^{23}=a_0+a_1+a_2+\dots +a_{23}$ for numerically greatest term $\frac{n+1}{1+|\frac{a}{b}|}=\frac{23+1}{1+\frac{5}{2}}=\frac{48}{7}$ $\Rightarrow \left[\frac{48}{7}\right]=6=\mathrm{m}$ (where [.] greatest integer function) so, ${\mathrm{T}}_7$ is numerical greatest term Hence $r=6$