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Mathematics - Binomial Theorem Question with Solution | TestHub

MathematicsBinomial TheoremRemainder and Divisibility ProblemsEasy2 minPYQ_2024

MathematicsEasynumerical

The remainder when $42 8^{2024}$ is divided by 21 is__________

Answer:

1.00

Solution:

$(428)^{2024} = (420 + 8)^{2024} = (21 \times 20 + 8)^{2024} = 21 m + 8^{2024}$
Now $8^{2024} = (8^{2})^{1012}$ $= (64)^{1012} = (63 + 1)^{1012} = (21 \times 3 + 1)^{1012} = 2 ln + 1$ $\Rightarrow$ Remainder is 1.

Stream:JEESubject:MathematicsTopic:Binomial TheoremSubtopic:Remainder and Divisibility Problems

⏱ 2mℹ️ Source: PYQ_2024

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