Mathematics - Binomial Theorem Question with Solution | TestHub

MathematicsBinomial TheoremGeneralMedium2 minPYQ_2021

MathematicsMediumsingle choice

Coefficient of $x^{13}$ in the expansion of $(1 - x)^{5} (1 + x + x^{2} + x^{3})^{4}$ is

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Solution:

Expression $= (1 - x)^{5} \cdot (1 + x)^{4} (1 + x^{2})^{4}$ $= (1 - x) (1 - x^{2})^{4} (1 + x^{2})^{4} = (1 - x) (1 - x^{4})^{4}$ $∴$ Coefficient of $x^{13} = -^{4} C_{3} (- 1)^{3} = 4$

Stream:BITSATSubject:MathematicsTopic:Binomial TheoremSubtopic:General

⏱ 2mℹ️ Source: PYQ_2021

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