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Mathematics - Binomial Theorem Question with Solution | TestHub

MathematicsBinomial TheoremLogarithmic and Exponential seriesMedium2 minPYQ_2016
MathematicsMediumnumerical

Let m be the smallest positive integer such that the coefficient ofx2in the expansion of1+x2+1+x3++1+x49+1+mx50is3n+1 51C3for some positive integer n.
Then the value of n is

Answer:
5.00
Solution:

Coefficient ofx2in the expansion of
1+x2+1+x3+1+x49+1+mx50is
2C2+3C2+49C2+50C2m2=3n+151C3
3C3+3C2+49C2+50C2m2=3n+151C3(Use n C r + n C r+1 = n+1 C r+1 )
50C3+50C2m2=3n+1 51C3
50.49.486+50.492 m2=3n+151.50.496
m2=51n+1must be a perfect square
By trial ⇒n=5andm=16(M,nN)
n =5

Stream:JEE_ADVSubject:MathematicsTopic:Binomial TheoremSubtopic:Logarithmic and Exponential series
2mℹ️ Source: PYQ_2016

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