The coefficient of x 9 in the expansion of 1 + x 1 + x 2 1 + x 3 … … 1 + x 100 is

Home

Mathematics - Binomial Theorem Question with Solution | TestHub

MathematicsBinomial TheoremGeneralEasy2 minPYQ_2015

MathematicsEasynumerical

The coefficient of $x^{9}$ in the expansion of $(1 + x) (1 + x^{2}) (1 + x^{3}) \dots \dots (1 + x^{100})$ is

Answer:

8.00

Solution:

$(1 + x) (1 + x^{2}) \dots . (1 + x^{100})$
Possible combination of 9 are (0, 9), (1, 8), (2, 7), (3, 6), (4, 5), (1, 2, 6), (1, 3, 5), (2, 3, 4)
So, coefficient = 8.

Stream:JEE_ADVSubject:MathematicsTopic:Binomial TheoremSubtopic:General

⏱ 2mℹ️ Source: PYQ_2015

Doubts & Discussion

Loading discussions...