Mathematics - Basic maths Question with Solution | TestHub

$\begin{array}{rl}& {\mathrm{e}}^{5(\ln x{)}^2+3}={\mathrm{x}}^8\\ & \Rightarrow \ell {\mathrm{ne}}^{5(\ln x{)}^2+3}=\ell {\mathrm{nn}}^8\\ & \Rightarrow 5(\ln \mathrm{x}{)}^2+3=8\ell \mathrm{nx}\\ & (\ell \mathrm{nx}=\mathrm{t})\\ & \Rightarrow 5{\mathrm{t}}^2-8\mathrm{t}+3=0\\ & {\mathrm{t}}_1+{\mathrm{t}}_2=\frac{8}{5}\\ & \ln {\mathrm{x}}_1{\mathrm{x}}_2=\frac{8}{5}\\ & {\mathrm{x}}_1{\mathrm{X}}_2={\mathrm{e}}^{8/5}\end{array}$