Mathematics - Basic maths Question with Solution | TestHub

3^x= 4^{x - 1}
x = (x - 1) log₃4
x ( 1 - 2 log₃2) = -2log₃2
$\text{x}=\frac{2{\text{log}}_{3}2}{2{\text{log}}_{3}2-1}$
x log₂3 = (x - 1).2
x (log₂3 - 2) = -2
$\text{x}=\frac{2}{2{-\text{log}}_{2}3}$
$\text{x}=\frac{1}{1-\frac{1}{2}{\text{log}}_{2}3}=\frac{1}{1-{\text{log}}_{4}3}$