Area bounded by 2 ≥ max . { ∣ x − y ∣ , ∣ x + y ∣ } is k sq. units then k =

2 ≥ max . { ∣ x − y ∣ , ∣ x + y ∣ } ⇒ ∣ x − y ∣ ≤ 2 and ∣ x + y ∣ ≤ 2 , which forms a square of diagonal length 4 units. ⇒ The area of the region is 2 1 × 4 × 4 = 8 sq. units This is equal to the area of the square of side length 2 2 .

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MathematicsArea Under CurvesArea bounded by Miscellaneous CurvesMedium2 minQB

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Area bounded by $2 \geq max . {∣ x - y ∣, ∣ x + y ∣}$ is k sq. units then $k =$

Answer:

Solution:

$2 \geq max . {∣ x - y ∣, ∣ x + y ∣}$

$\Rightarrow ∣ x - y ∣ \leq 2$ and $∣ x + y ∣ \leq 2$ , which forms a square of diagonal length 4 units.

⇒ The area of the region is $\frac{1}{2} \times 4 \times 4 = 8$ sq. units

This is equal to the area of the square of side length $22$ .

Stream:JEESubject:MathematicsTopic:Area Under CurvesSubtopic:Area bounded by Miscellaneous Curves

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