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Mathematics - Area Under Curves Question with Solution | TestHub

MathematicsArea Under CurvesArea bounded by two curvesMedium2 minQB

MathematicsMediumsingle choice

Find the area bounded by $y = - x^{2} + 6 x - 5, y = - x^{2} + 4 x - 3$ , and $y = 3 x - 15$ for $x > 1$ .

Options:

Answer:

Solution:

The relevant intersections split the region at $x = 4$ . Thus $A = \int_{1}^{4} [(- x^{2} + 6 x - 5) - (- x^{2} + 4 x - 3)] d x + \int_{4}^{5} [(- x^{2} +$ $\underline{6 x - 5}) - (3 x - 15)] d x = 73/6$ .

Stream:JEESubject:MathematicsTopic:Area Under CurvesSubtopic:Area bounded by two curves

⏱ 2mℹ️ Source: QB

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