Mathematics - Area Under Curves Question with Solution | TestHub

MathematicsArea Under CurvesArea bounded by Miscellaneous CurvesMedium2 minQB

MathematicsMediumsingle choice

Area bounded by $y = f^{- 1} (x)$ and tangent and normal drawn to it at the points with abscissae $π$ and $2 π$ , where $f (x) = sin x - x$ is

Answer:

Solution:

Required area $A = \int_{π}^{2 π} ((sin x - x) + 2 π) d x = \frac{π ^{2}}{2} - 2$ sq.units.

Stream:JEESubject:MathematicsTopic:Area Under CurvesSubtopic:Area bounded by Miscellaneous Curves

⏱ 2mℹ️ Source: QB

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