Mathematics - Area Under Curves Question with Solution | TestHub

$A\Rightarrow$ Rectangle ABDE - Area of region EDC $\begin{array}{rl}& A\Rightarrow 4-2{\int }_0^1(3-x)-\left(\frac{x^2+3}{2}\right)dx\\ & A\Rightarrow 4-2{\left\{3x-\frac{x^2}{2}-\frac{x^3}{6}-\frac{3}{2}x\right\}}_0^1\\ & A\Rightarrow 4-2\left\{3-\frac{1}{2}-\frac{1}{6}-\frac{3}{2}\right\}=\frac{7}{3}\end{array}$ So $6\mathrm{A}=14$