Area (in sq. units) of the region outside x 2 + y 3 = 1 and inside the ellipse x 2 4 + y 2 9 = 1 is

Area of ellipse = π a b = 6 π Area enclosed by | x | 2 + | y | 3 = 1 is = 4 × 1 2 2 3 = 12 So, required area = 6 π - 12 sq. units

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Mathematics - Area Under Curves Question with Solution | TestHub

MathematicsArea Under CurvesArea bounded by Miscellaneous CurvesHard2 minPYQ_2020

MathematicsHardsingle choice

Area (in sq. units) of the region outside $\frac{|x|}{2} + \frac{|y|}{3} = 1$ and inside the ellipse $\frac{x^{2}}{4} + \frac{y^{2}}{9} = 1$ is

Question diagram: Area (in sq. units) of the region outside x 2 + y 3 = 1 and

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Answer:

Solution:

Area of ellipse $= π a b = 6 π$
Area enclosed by $\frac{| x |}{2} + \frac{| y |}{3} = 1$ is
$= 4 \times \frac{1}{2} (2) (3) = 12$
So, required area $= 6 π - 12$ sq. units

Stream:JEESubject:MathematicsTopic:Area Under CurvesSubtopic:Area bounded by Miscellaneous Curves

⏱ 2mℹ️ Source: PYQ_2020

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