The area of the region enclosed by the curves y = x , x = e , y = x 1 and the positive x -axis is

Area = ∫ 0 1 x d x + ∫ 1 e x 1 d x = 2 1 + 1 = 2 3

Mathematics - Area Under Curves Question with Solution | TestHub

MathematicsArea Under CurvesArea bounded by Miscellaneous CurvesMedium2 minPYQ_2011

MathematicsMediumsingle choice

The area of the region enclosed by the curves $y = x, x = e, y = \frac{1}{x}$ and the positive $x$ -axis is

Answer:

Solution:

Area $= \int_{0}^{1} x d x + \int_{1}^{e} \frac{1}{x} d x = \frac{1}{2} + 1 = \frac{3}{2}$

Stream:JEESubject:MathematicsTopic:Area Under CurvesSubtopic:Area bounded by Miscellaneous Curves

⏱ 2mℹ️ Source: PYQ_2011

Loading discussions...