Mathematics - Area Under Curves Question with Solution | TestHub

$\begin{array}{rl}& \text{ Hints: }A={\int }_0^4\left(\sqrt{4\mathrm{x}}-\frac{{\mathrm{x}}^2}{4}\right)\mathrm{dx}\\ & =2\cdot \frac{2}{3}{\left({\mathrm{x}}^{3/2}\right)}_0^4-\frac{1}{4.3}){\left({\mathrm{x}}^3\right)}_0^4\\ & =\frac{4}{3}\left[4^{3/2}-0\right]-\frac{1}{4.3}\left[4^3-0\right]\\ & =\frac{4^{5/2}}{3}-\frac{16}{3}=\frac{32-16}{3}=\frac{16}{3}\end{array}$