The value of 1 + s i n θ c o s θ is equal to

1 + sin θ cos θ = 1 + cos ( 2 π − θ ) sin ( 2 π − θ ) = 2 cos 2 ( 4 π − 2 θ ) 2 sin ( 4 π − 2 θ ) cos ( 4 π − 2 θ ) = cos ( 4 π − 2 θ ) sin ( 4 π − 2 θ ) = tan ( 4 π − 2 θ )

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Mathematics - Area Under Curves Question with Solution | TestHub

MathematicsArea Under CurvesArea bounded by two curvesEasy2 minPYQ_2010

MathematicsEasysingle choice

The value of $\frac{c o s θ}{1 + s i n θ}$ is equal to

Options:

Answer:

Solution:

$\frac{cos θ}{1 + sin θ} = \frac{sin ( \frac{π}{2} - θ )}{1 + cos ( \frac{π}{2} - θ )} = \frac{2 sin ( \frac{π}{4} - \frac{θ}{2} ) cos ( \frac{π}{4} - \frac{θ}{2} )}{2 cos ^{2} ( \frac{π}{4} - \frac{θ}{2} )} = \frac{sin ( \frac{π}{4} - \frac{θ}{2} )}{cos ( \frac{π}{4} - \frac{θ}{2} )} = tan (\frac{π}{4} - \frac{θ}{2})$

Stream:VITEEESubject:MathematicsTopic:Area Under CurvesSubtopic:Area bounded by two curves

⏱ 2mℹ️ Source: PYQ_2010

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