Mathematics - Application of Derivative Question with Solution | TestHub

$x=8{\cos }^3\theta ,y=8{\sin }^3\theta ,\frac{dy}{dx}=-\frac{\sin \theta }{\cos \theta }$ Tangent at $\theta :y-8{\sin }^3\theta =-\frac{\sin \theta }{\cos \theta }\left(x-8{\cos }^3\theta \right)\Rightarrow x\sin \theta +y\cos \theta =8\sin \theta \cos \theta$ $OA=8\cos \theta ,OB=8\sin \theta ;AB=\sqrt{O{A}^2+O{B}^2}=8$