Mathematics - Application of Derivative Question with Solution | TestHub

Let $P\left(x_0,y_0\right)$ be the nearest point $\begin{array}{rlrl}P{A}^2& ={\left(y_0-3\right)}^2+{\left(x_0-0\right)}^2& =y_0^2-4y_0+9\text{ as }{x}_0^2=2y_0& ={\left(y_0-2\right)}^2+5\end{array}$ $P{A}^2$ is minimum if $y_0=2;x_0=\pm 2$ $P(\pm 2,2)$. Aliter : A lies on normal to curve at $P$.