Mathematics - Application of Derivative Question with Solution | TestHub

At x-axis, $y=0\Rightarrow x=1$ $x+y=x^y\Rightarrow \ln (x+y)=y\ln x\Rightarrow \frac{1}{x+y}\left(1+\frac{dy}{dx}\right)=\frac{y}{x}+\frac{dy}{dx}\ln x$ ${\left(\frac{dy}{dx}\right)}_{(1,0)}=-1$. So equation of normal: $y-0=x-1$