IF A > 0 , B < 0 AND A = 3 π + B THEN MINIMUM VALUE OF TAN A TAN B IS

B 0 = − B > 0 ; A + B 0 = 3 π . By A.M.-G.M., max tan A tan B 0 happens when

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MathematicsApplication of DerivativeMaxima-MinimaMedium2 minQB

MathematicsMediumsingle choice

IF $A > 0, B < 0$ AND $A = \frac{π}{3} + B$ THEN MINIMUM VALUE OF TAN $A$ TAN $B$ IS

Answer:

Solution:

$B_{0} = - B > 0; A + B_{0} = \frac{π}{3}$ . By A.M.-G.M., max $tan A tan B_{0}$ happens when

Stream:JEESubject:MathematicsTopic:Application of DerivativeSubtopic:Maxima-Minima

⏱ 2mℹ️ Source: QB

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