Mathematics - Application of Derivative Question with Solution | TestHub

The maximum possible values is 2

$\sin (x/3)$ TAKES THE VALUES 1 WHEN

$\begin{array}{rlr}& x/3=2n\pi +\pi /2& \text{ I.E }x/3=90+360m\end{array}$

$\sin (x/11)$ TAKES THE VALUE 1

WHEN $x/11=2n\pi +\pi /2$ I.E $x/11=90+360n$

WE ARE LOOKING FOR A COMMON SOLUTION WE HAVE $3m-11n=2$. THEN SMALLEST POSITIVE SOLUTION TO THIS IS $m=8,n=2$,

THUS $x_0=8910^0$, GIVING $\alpha =8910$