The minimum value of f ( x ) = x 2 + x 250 is

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MathematicsApplication of DerivativeMaxima-MinimaEasy2 minQB

MathematicsEasysingle choice

The minimum value of $f (x) = x^{2} + \frac{250}{x}$ is

Answer:

Solution:

$f^{'} (x) = 0$ and $f^{''} (5) > 0$ minimum value $= f (5)$

Stream:JEESubject:MathematicsTopic:Application of DerivativeSubtopic:Maxima-Minima

⏱ 2mℹ️ Source: QB

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