Mathematics - Application of Derivative Question with Solution | TestHub
MathematicsApplication of DerivativeTangents & NormalsMedium2 minQB
MathematicsMediumsingle choice
Match the following.
(a) The tangent at any point on the curve divides the abscissa of the point of contact in the ratio . Then is equal to ( are co-prime) | (P) 0 |
|---|---|
(b) The area of the triangle formed by the normal at the point on the curve with the co-ordinate axes is | (Q) 1/2 |
(c) If the angle between the curves and at the point is , then is equal to | (R) 4 |
(d) The length of the subtangent at any point on the curve is equal to | (S) 3 |
Options:
Answer:
A
Solution:
(a) . Tangent at meets the x-axis at , which divides the abscissa in the ratio 1 : 3, so (R) . (b) at (1, 0); the normal is , area (Q). (c) Both curves have slope -2 at (1, 1), so and (P). (d) Subtangent (S).
Stream:JEESubject:MathematicsTopic:Application of DerivativeSubtopic:Tangents & Normals
⏱ 2mℹ️ Source: QB
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