Mathematics - Application of Derivative Question with Solution | TestHub

MathematicsApplication of DerivativeMonotonicity-LMVTMedium2 minQB

MathematicsMediumsingle choice

$f (x) = {x^{a} ln x 0 : x > 0 : x = 0$

If Lagrange’s theorem applies to $f (x)$ on $[0, 1]$ , then 'a' can be:

Answer:

Solution:

$f$ is continuous at $x = 0$ $∴ 0 = lim_{x \to 0 +} f (x) = lim_{x \to 0 +} x^{a} ln x forces " a > 0 " is necessary.$

Stream:JEESubject:MathematicsTopic:Application of DerivativeSubtopic:Monotonicity-LMVT

⏱ 2mℹ️ Source: QB

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