The sum of all the integral values of K such that the variable point $(K, \frac{1}{K})$ remains on or inside the triangle formed by the x -axis and the tangents drawn at $(2, 1)$ on the curve $y = e^{- ∣ x - 2∣}$ is,
Answer:
2
Solution:
$\frac{1 + 5}{2} \leq K \leq \frac{3 + 5}{2} \Rightarrow$ hence $K = 2$

Question

The sum of all the integral values of K such that the variable point $(K, \frac{1}{K})$ remains on or inside the triangle formed by the x -axis and the tangents drawn at $(2, 1)$ on the curve $y = e^{- ∣ x - 2∣}$ is,

Answer:

2

Solution:

$\frac{1 + 5}{2} \leq K \leq \frac{3 + 5}{2} \Rightarrow$ hence $K = 2$

TestHub · Accepted Answer

2 1 + 5 ​ ​ ≤ K ≤ 2 3 + 5 ​ ​ ⇒ hence K = 2

Mathematics - Application of Derivative Question with Solution | TestHub

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