Mathematics - Application of Derivative Question with Solution | TestHub

MathematicsApplication of DerivativeMaxima-MinimaMedium2 minPYQ_2018
MathematicsMediumsingle choice

LetMandmbe respectively the absolute maximum and the absolute minimum values of the function,fx=2x3-9x2+12x+5in the interval[0,3]. ThenM-mis equal to

Options:

Answer:
A
Solution:

Given fx=2x3-9x2+12x+5, x∈0,3

Differentiating w.r.t x,

⇒f′x=6x2-18x+12

⇒f′x=6x-1x-2

For maxima/minima f'x=0

⇒6x-1x-2=0⇒x=1,2

Now, f"x=12x-18

So at x=1, f"x<0

and at x=2, f"x>0

So, for absolute maxima/minima

⇒f1=10

⇒f2=9

⇒f0=5

⇒f3=14

⇒M=14

⇒m=5

∴ M-m=9

Stream:JEESubject:MathematicsTopic:Application of DerivativeSubtopic:Maxima-Minima
⏱ 2mℹ️ Source: PYQ_2018

Doubts & Discussion

Loading discussions...