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Mathematics - Application of Derivative Question with Solution | TestHub

MathematicsApplication of DerivativeMaxima-MinimaMedium2 minPYQ_2018
MathematicsMediumsingle choice

LetMandmbe respectively the absolute maximum and the absolute minimum values of the function,fx=2x3-9x2+12x+5in the interval[0,3]. ThenM-mis equal to

Options:

Answer:
A
Solution:

Given fx=2x3-9x2+12x+5, x0,3

Differentiating w.r.t x,

fx=6x2-18x+12

fx=6x-1x-2

For maxima/minima f'x=0

6x-1x-2=0x=1,2

Now, f"x=12x-18

So at x=1, f"x<0

and at x=2, f"x>0

So, for absolute maxima/minima

f1=10

f2=9

f0=5

f3=14

M=14

m=5

∴ M-m=9

Stream:JEESubject:MathematicsTopic:Application of DerivativeSubtopic:Maxima-Minima
2mℹ️ Source: PYQ_2018

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