If lo g α 8 = γ , lo g β α = − 1 , and lo g 1/4 β = − 1 , evaluate ( α 1 + 1 ) l o g 5 ( β 2 + 4 γ 2 ) .

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If $lo g_{α} 8 = γ, lo g_{β} α = - 1$ , and $lo g_{1/4} β = - 1$ , evaluate $(\frac{1}{α} + 1)^{l o g_{5} (β^{2} + 4 γ^{2})}$ .

Answer:

Solution:

$β = 4, α = 1/4$ , and $γ = - 3/2$ . The base is 5 and the exponent is $lo g_{5} 25 = 4$ , giving 625.

Stream:JEESubject:MathematicsTopic:Algebra-MixedSubtopic:Algebra-Mixed

⏱ 3mℹ️ Source: QB

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