Mathematics - 3D-Coordinate Geometry Question with Solution | TestHub

The plane can be written as $\frac{x}{-6}+\frac{y}{-2}+\frac{z}{3/2}=1$. The intercepts are $-6,-2,\frac{3}{2}$ and the required sum is $-6-2+\frac{3}{2}=-\frac{13}{2}$.