Mathematics - 3D-Coordinate Geometry Question with Solution | TestHub

Mathematics3D-Coordinate GeometryLine ( Equation etc.)Medium2 minQB

MathematicsMediummultiple choice

OAB is an isosceles triangle with $OA = OB$ . If O is origin, A is (-20, -6, -5) and equation of base AB is $\frac{x + 16}{2} = \frac{y}{3} = \frac{z + 1}{2}$ , then -

Options:(select one or more)

Answer:

A, C

Solution:

Drop the perpendicular from O to the base at D. Since OA=OB, D is the midpoint of AB. This gives the height and the second vertex: $D = (- 16 + 2 t, 3 t, - 1 + 2 t), D \cdot (2, 3, 2) = 17 t - 34 = 0, t = 2, D = (- 12, 6, 3) . O D = 189 = 321, N = 21. B = 2 D - A = (- 4, 18, 11), a + b + c = 25. Correct: A and C.$

Stream:JEESubject:MathematicsTopic:3D-Coordinate GeometrySubtopic:Line ( Equation etc.)

⏱ 2mℹ️ Source: QB

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