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Mathematics - 3D Coordinate Geometry Question with Solution | TestHub

Mathematics3D Coordinate GeometryEquation of the bisector planes, Angle between two planesMedium2 minQB

MathematicsMediumsingle choice

Equation of a plane bisecting the angle between the planes $2 x - y + 2 z + 3 = 0$ and $3 x - 2 y + 6 z + 8 = 0$ is

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The bisecting planes are $\frac{2 x - y + 2 z + 3}{3} = \pm \frac{3 x - 2 y + 6 z + 8}{7}$ , i.e. $7 (2 x - y + 2 z + 3) = \pm 3 (3 x - 2 y + 6 z + 8)$ . The + sign gives $5 x - y - 4 z - 3 = 0$ and the - sign gives $23 x - 13 y + 32 z + 45 = 0$ .

Stream:JEESubject:MathematicsTopic:3D Coordinate GeometrySubtopic:Equation of the bisector planes, Angle between two planes

⏱ 2mℹ️ Source: QB

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