Mathematics - 3D Coordinate Geometry Question with Solution | TestHub

The given point is $P(2,3,4)$.

The distance of a point $P(x,y,z)$ from the XY plane is given by $|z|$.

$a=|4|=4$

The distance of a point $P(x,y,z)$ from the Y-axis is given by $\sqrt{x^2+z^2}$.

$b=\sqrt{2^2+4^2}=\sqrt{4+16}=\sqrt{20}$

We need to find the value of $a^2+b^2$.

$a^2+b^2=4^2+(\sqrt{20}{)}^2=16+20=36$

Answer: $36$