Mathematics - 3D Coordinate Geometry Question with Solution | TestHub

Equation of the plane containing $\frac{x}{3}=\frac{y}{4}=\frac{z}{2}$ and $\frac{x}{4}=\frac{y}{2}=\frac{z}{3}$ is $$\begin{array}{rl}& \left|\begin{array}{ccc}x& y& z\\ 3& 4& 2\\ 4& 2& 3\end{array}\right|=0\\ & \Rightarrow 8x-y-10z=0\end{array}$$ Now required plane is perpendicular to this plane. Consider option (C) $$(8)(1)+(-1)(-2)+(-10)(1)=0$$