Mathematics - 3D Coordinate Geometry Question with Solution | TestHub

The equation of plane containing the line of intersection of the planes $2x-y-4=0$ and $y+2z-4=0$ is $(2x-y-4)+\lambda (y+2z-4)=0$ But it passes through $(1,1,0)$ $\Rightarrow \lambda =-1$ $\Rightarrow$ The required equation of plane is $\begin{array}{rl}& (2x-y-4)-(y+2z-4)=0\\ & \Rightarrow 2x-2y-2z=0\\ & \Rightarrow x-y-z=0\end{array}$