Mathematics - 3D Coordinate Geometry Question with Solution | TestHub

Mathematics3D Coordinate GeometryPlane (Equations)Easy2 minPYQ_2022

MathematicsEasysingle choice

The co-ordinates of the foot of the perpendicular drawn form the origin to the plane $3 x + 2 y + 6 z = 56$ is

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Answer:

Solution:

$\frac{x - 0}{3} = \frac{y - 0}{2} = \frac{z - 0}{6} = \frac{- ( 3 \times 0 + 2 \times 0 + 1 \times 0 - 56 )}{3 ^{2} + 2 ^{2} + 6 ^{2}} \Rightarrow \frac{x}{3} = \frac{y}{2} = \frac{z}{6} = \frac{56}{49} \Rightarrow x = \frac{24}{7}, y = \frac{16}{7}, z = \frac{48}{7} \Rightarrow (\frac{24}{7}, \frac{16}{7}, \frac{48}{7})$

Stream:MHT_CETSubject:MathematicsTopic:3D Coordinate GeometrySubtopic:Plane (Equations)

⏱ 2mℹ️ Source: PYQ_2022

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