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Mathematics - 3D Coordinate Geometry Question with Solution | TestHub

Mathematics3D Coordinate GeometryPlane (Equations)Medium2 minPYQ_2022

MathematicsMediumsingle choice

The cartesian equation of a line passing through $(1, 2, 3)$ and parallel to planes $x - y + 2 z = 5$ and $3 x + y + z = 6$ is

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Solution:

Required equation $\frac{x - 1}{( - 1 ) \times 1 - 1 \times 2} = \frac{y - 2}{3 \times 2 - 1 \times 1} = \frac{z - 3}{1 \times 1 - 3 \times ( - 1 )} \Rightarrow \frac{x - 1}{- 3} = \frac{y - 2}{5} = \frac{z - 3}{4}$

Stream:MHT_CETSubject:MathematicsTopic:3D Coordinate GeometrySubtopic:Plane (Equations)

⏱ 2mℹ️ Source: PYQ_2022

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