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Mathematics - 3D Coordinate Geometry Question with Solution | TestHub

Mathematics3D Coordinate GeometryPlane (Equations)Medium2 minPYQ_2022

MathematicsMediumsingle choice

The equation of the plane through the intersection of the planes $x + y + z = 1$ and $2 x + 3 y - x + 4 = 0$ and parallel to $X$ -axis is

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Solution:

$(x + y + z - 1) + λ (2 x + 3 y - z + 4) = 0 \Rightarrow (1 + 2 λ) x + (1 + 3 λ) y + (1 - λ) z + (4 λ - 1) = 0$ To be parallel to the $x$ -axis $1 + 2 λ = 0 \Rightarrow λ = \frac{- 1}{2}$ $\Rightarrow - \frac{1}{2} y + \frac{3}{2} z - 3 = 0 \Rightarrow y - 3 z + 6 = 0$

Stream:MHT_CETSubject:MathematicsTopic:3D Coordinate GeometrySubtopic:Plane (Equations)

⏱ 2mℹ️ Source: PYQ_2022

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