The vectors AB = 3 i ^ + 4 k ^ and AC = 5 i ^ − 2 k ^ + 4 k ^ are the sies of a triangle ABC . The length of the median through A is

Let A be the origin. Then B = ( 3 , 0 , 4 ) and C = ( 5 , − 1 , 4 ) Mid point of BC = ( 2 3 + 5 , 2 0 − 2 , 2 4 + 4 ) i.e. ( 4 , − 1 , 4 ) ∴ Length of medium = ( 4 ) 2 + ( − 1 ) 2 + ( 4 ) 2 = 33

Start Free Mock LoginAlready registered? Login here

Mathematics - 3D Coordinate Geometry Question with Solution | TestHub

Mathematics3D Coordinate GeometryCoordinates of a point in space, Direction cosines,Easy2 minPYQ_2021

MathematicsEasysingle choice

The vectors $AB = 3 \hat{i} + 4 \hat{k}$ and $AC = 5 \hat{i} - 2 \hat{k} + 4 \hat{k}$ are the sies of a triangle $ABC$ . The length of the median through $A$ is

Options:

Answer:

Solution:

Let $A$ be the origin. Then $B = (3, 0, 4)$ and $C = (5, - 1, 4)$ Mid point of $BC = (\frac{3 + 5}{2}, \frac{0 - 2}{2}, \frac{4 + 4}{2})$ i.e. $(4, - 1, 4)$ $∴$ Length of medium $= (4)^{2} + (- 1)^{2} + (4)^{2} = 33$

Stream:MHT_CETSubject:MathematicsTopic:3D Coordinate GeometrySubtopic:Coordinates of a point in space, Direction cosines,

⏱ 2mℹ️ Source: PYQ_2021

Doubts & Discussion

Loading discussions...