Mathematics - 3D Coordinate Geometry Question with Solution | TestHub

Mathematics3D Coordinate GeometryPlane (Equations)Easy2 minPYQ_2020

MathematicsEasysingle choice

The distance of a point $(1, 2, - 1)$ from the plane $x - 2 y + 4 z + 10 = 0$ is

Answer:

Solution:

(D) $Required distance = \frac{∣1 ( 1 ) + - 2 ( 2 ) + 4 ( - 1 ) + 10∣}{1 ^{2} + ( - 2 ) ^{2} + ( 4 ) ^{2}} = \frac{3}{21} = \frac{3}{7} units$

Stream:MHT_CETSubject:MathematicsTopic:3D Coordinate GeometrySubtopic:Plane (Equations)

⏱ 2mℹ️ Source: PYQ_2020

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