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Mathematics - 3D Coordinate Geometry Question with Solution | TestHub

Mathematics3D Coordinate GeometryPlane (Equations)Medium2 minPYQ_2017

MathematicsMediumsingle choice

The equation of the plane through $(- 1, 1, 2),$ whose normal makes equal acute angle with co-ordinate axes is

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Solution:

Equation plane passing through
$A (\vec{a})$ and $⊥$ to $\vec{n}$ is
$\vec{r} . \vec{n} = \vec{a} . \vec{n}$
Here $\vec{a} = - \hat{i} + \hat{j} + 2 \hat{k}, \vec{n} = \hat{i} + \hat{j} + \hat{k}$
$∴ \vec{r} \cdot (\hat{i} + \hat{j} + \hat{k}) = (- \hat{i} + \hat{j} + 2 \hat{k}) . (\hat{i} + \hat{j} + \hat{k}) = 2$

Stream:MHT_CETSubject:MathematicsTopic:3D Coordinate GeometrySubtopic:Plane (Equations)

⏱ 2mℹ️ Source: PYQ_2017

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