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Mathematics - 3D Coordinate Geometry Question with Solution | TestHub

Mathematics3D Coordinate GeometryPlane (Equations)Easy2 minPYQ_2010

MathematicsEasysingle choice

The equation of the plane which passes through $(2, - 3, 1)$ and is normal to the line joining the points $(3, 4, - 1)$ and $(2, - 1, 5)$ , is given by

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Answer:

Solution:

The equation of plane is $(x - 2) + 5 (y + 3) - 6 (z - 1) = 0 \Rightarrow x + 5 y - 6 z + 19 = 0$

Stream:MHT_CETSubject:MathematicsTopic:3D Coordinate GeometrySubtopic:Plane (Equations)

⏱ 2mℹ️ Source: PYQ_2010

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