If z = 1 + i 3 1 − i 3 , then arg ( z ) is

z = ( 1 + i 3 1 − i 3 ) ⇒ z = 1 + i 3 1 − i 3 × 1 − i 3 1 − i 3 ⇒ z = 1 + 3 1 − 3 − 2 3 i = 4 − 2 − 2 3 i ⇒ z = − 2 1 − 2 3 i Thus, ar g ( z ) = 24 0 ∘

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Mathematics - 3D-Coordinate Geometry Question with Solution | TestHub

Mathematics3D-Coordinate GeometryMiscellaneous/MixedHard2 minPYQ_2010

MathematicsHardsingle choice

If $z = \frac{1 - i 3}{1 + i 3}$ , then arg $(z)$ is

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$z = (\frac{1 - i 3}{1 + i 3}) \Rightarrow z = \frac{1 - i 3}{1 + i 3} \times \frac{1 - i 3}{1 - i 3} \Rightarrow z = \frac{1 - 3 - 2 3 i}{1 + 3} = \frac{- 2 - 2 3 i}{4} \Rightarrow z = - \frac{1}{2} - \frac{3}{2} i Thus, ar g (z) = 24 0^{\circ}$

Stream:VITEEESubject:MathematicsTopic:3D-Coordinate GeometrySubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2010

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